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UGC NET JUNE 2012 DATA COLLECTION ON INDIVIDUAL MARKS OBTAINED AS PER ANSWER KEY
DEAR PROFESSIONALS
I Kindly request all professionals to mention your marks obtained as per the answer keys announced by the UGC as it is going to be helpful for the estimation of final preparation of result and it will help to identify ranking
thanking you
kindly go through the link
Views: 11086
Replies to This Forum
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Permalink Reply by Dr. Rupesh Gaur on
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The score is according to anskeys provided by the UGC are as under follow:
Paper No.of correct question Obtained Marks
1st 34 34X2=68
2nd 31 31X2=62
3rd 52 52X2=104
Total Score 117 117X2=234
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Permalink Reply by Rahul LR on
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sir, my scores are,
Paper I=35 answrs right
Paper II=37 answrs right
Paper III=36 answrs right
(Category= OBC)
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Permalink Reply by yogesh dusankar on
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The score is according to anskeys provided by the UGC are as under follow:
Category : Open/General
Paper No.of correct question Obtained Marks
1st 24 24X2= 48
2nd 22 22X2=44
3rd 33 33X2=66
Shall I clear UGC NET 2012
Thanks and Regards
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final score is 158 marks
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Permalink Reply by 2a99408gz9kim on
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Please reply me what is the final score for NET
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Hello Friends Good Morning to all
I am Mr.M.Ravi Kumar,
My scores are
Paper-I 29x2 = 58
Paper-II 30x2 = 30
Paper-III 49x2 = 98
Total =216
Category OBC
Andhra Pradesh
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Permalink Reply by urmila sharma on
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paper-i 60
paper-ii 68
paper-iii 112
total 240
cat-gen
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Permalink Reply by Mahendra Krishna Humane on
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My Score is
Paper 1 = 30
Paper 2 = 30
Paper 3 = 41
From General Category
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Permalink Reply by Ashok Bhatt on
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My Scores according to the Answer Keys provided are as below:
Paper No.of correct question Obtained Marks
1st 29 29X2=58
2nd 31 31X2=62
3rd 41 41X2=82
Total Score 101 101X2=202
Category -------- GEN
HIMACHAL PRADESH
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Permalink Reply by Annu Srivastava on
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My scores-
Paper 1= 33(66%)
Paper 2= 37(74%)
Paper 3= 44(58.66%)
Here i would like to clear one thing that most of my friends are confused about calculating the percentage of marks of third paper. They are calculating it out of 50 questions, while the number of questions were 75. So according to me the formula of calculation is-
no. of questions correct*100/75.
OR
no. of marks*100/Total marks
(Here each question was of 2 marks and Total marks were 150. So suppose if you have 45 correct questions then your calculation will be-
(45*2)*100/150
=90*100/150
=9000/150
=60%
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Permalink Reply by Dr Shivakumar T C on
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Ist paper-44 (22), IInd Paper-58 (29), IIIrd Paper-88 (44), SC candidate
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Permalink Reply by Manjunatha Kannasandra on
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paper - I 32 Q correct 64
Paper - II 30 Q Correct 60
Paper -II 44 Q Correct 88
Total - 212
Category- OBC
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